3x-4(x^(1/2))-7=0

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Solution for 3x-4(x^(1/2))-7=0 equation:


D( x )

x < 0

x < 0

x in <0:+oo)

3*x-(4*x^(1/2))-7 = 0

3*x-4*x^(1/2)-7 = 0

t_1 = x^(1/2)

3*t_1^2-4*t_1^1-7 = 0

3*t_1^2-4*t_1-7 = 0

DELTA = (-4)^2-(-7*3*4)

DELTA = 100

DELTA > 0

t_1 = (100^(1/2)+4)/(2*3) or t_1 = (4-100^(1/2))/(2*3)

t_1 = 7/3 or t_1 = -1

t_1 = -1

x^(1/2)+1 = 0

1*x^(1/2) = -1 // : 1

x^(1/2) = -1

( -1 < 0 i 1/2 in (0:1) ) => x naleu017Cy do O

t_1 = 7/3

x^(1/2)-7/3 = 0

1*x^(1/2) = 7/3 // : 1

x^(1/2) = 7/3

x^(1/2) = 7/3 // ^ 2

x = 49/9

x = 49/9

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